Math (geometry problem)

[talltexasshoote]

Give me a grinder and I'll make it fit

This. After that I can pump out as many as you need with flat stock and a grinder.

[Dale Moser]

I would figure the leg length of that right triangle, (A squared +B squared=C squared), and work from there, but I'm not going to because you already have your answer.

[Goldeneagle]

Would like to see it drawn out and the math worked through on paper, I still can't figure out all the angles on paper.

The best I can see on any of the triangles is one side. Need two sides or one side and an angle.

[JustinJ]

The best I can see on any of the triangles is one side. Need two sides or one side and an angle.

Yup!

[cbd10pt]

The best I can see on any of the triangles is one side. Need two sides or one side and an angle.

Rhombus is parallel so you have both sides.
Of course a squared plus b squared = c squared will allow you to figure out C.
Once you have a, b and c you will also have your rise and run. Easy conversion to angle from there

[meltingfeather]

I don't think there is enough info to get it by trig.
Rafter layout doesn't get to the math-- You just take the measurements you need and make it fit.

[meltingfeather]

Rhombus is parallel so you have both sides.
Of course a squared plus b squared = c squared will allow you to figure out C.
Once you have a, b and c you will also have your rise and run. Easy conversion to angle from there

Do it then.
Everyone can squirt a few drops of HS trig they remember, but this problem is not as simple as you're trying to make it sound.

[Dale Moser]

On 2nd look, I can't get there from here. I could make it fit though!


That's gonna be a tiny gate...

[JustinJ]

Rhombus is parallel so you have both sides.
Of course a squared plus b squared = c squared will allow you to figure out C.
Once you have a, b and c you will also have your rise and run. Easy conversion to angle from there

Don't have any of the sides. Opposite sides are parallel. I only know the length of a perpendicular line between the two longest sides is .5". If the rectangle that it fits in changed, this measurement would stay stay the same but all the other measurements would change.

I know there is enough info there to get to the correct answer. Just don't know how.

[Charrison]

You lost me at rhombus.

Heck of a player for the LA Lakers in the 80s.

[JustinJ]

Math (geometry problem)

On 2nd look, I can't get there from here. I could make it fit though!





That's gonna be a tiny gate...

Haha just deco pieces to go in-between the top rail and a piece of channel welded 4" from the top.

[175gr7.62]

Only way to solve this is using a system of equations. You can't do it with a simple trigonometric identity alone. CAD is your friend here.....

[JustinJ]

Only way to solve this is using a system of equations. You can't do it with a simple trigonometric identity alone. CAD is your friend here.....

Agreed. I know there is enough information to come up with the answer, because there is only one solution, but just not sure how to get there.

[meltingfeather]

Only way to solve this is using a system of equations. You can't do it with a simple trigonometric identity alone. CAD is your friend here.....

there are as many unknowns as equations...

[Goldeneagle]

Rhombus is parallel so you have both sides.
Of course a squared plus b squared = c squared will allow you to figure out C.
Once you have a, b and c you will also have your rise and run. Easy conversion to angle from there

Lets see some numbers.